

In the below program we will see how to access an element of an array using the echo function.

Now we will see an example below having an invalid JSON format and passing this string to the json_decode() function and what error and output it will give and we will also how to print those array which can be accessed using the “echo” function in the below section. Suppose we have not set anything or not passed asso_arr parameter such as “var_dump(json_decode($json_string)) ” then this value would give us access to the property of the object in an array as shown in the below screenshot.

It has array(5) which means it has 5 elements in an array. In the above code, we can are declaring a JSON variable as json_string in which we are storing the JSON format data to be converted and then this variable is passed as a parameter to json_decode() function with asso_arr set as “true” that gives it in an array format as shown in the above screenshot.
#Php json decode error code
In the above program, we can see when we are writing PHP code in HTML structure we start with “”. Examples of PHP json_decodeįollowing are the examples are given below: Example #1 Now let us see simple example which uses json_decode() of PHP in a HTML structure. This json_decode() function of PHP takes JSON encoded string as input and returns the value that is decoded to PHP objects which of PHP data types and if the decoding is not possible then this function returns null instead of PHP objects.
